5x^2+10x-16=4x

Solution for 5x^2+10x-16=4x equation:

5x^2+10x-16=4x

We move all terms to the left:

5x^2+10x-16-(4x)=0

We add all the numbers together, and all the variables

5x^2+6x-16=0

a = 5; b = 6; c = -16;
Δ = b2-4ac
Δ = 62-4·5·(-16)
Δ = 356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{356}=\sqrt{4*89}=\sqrt{4}*\sqrt{89}=2\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{89}}{2*5}=\frac{-6-2\sqrt{89}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{89}}{2*5}=\frac{-6+2\sqrt{89}}{10}
$